WBJEE · Maths · Ellipse
\(A B\) is a variable chord of the ellipse \(\frac{x^2}{a^2}+\frac{y^2}{b^2}=1\). If \(A B\) subtends a right angle at the origin \(O\), then \(\frac{1}{OA^2}+\frac{1}{OB^2}\) equals to
- A \(\frac{1}{a^2}+\frac{1}{b^2}\)
- B \(\frac{1}{a^2}-\frac{1}{b^2}\)
- C \(a^2+b^2\)
- D \(a^2-b^2\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{a^2}+\frac{1}{b^2}\)
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