WBJEE · Maths · Circle
The circles \(\mathrm{x}^2+\mathrm{y}^2-10 \mathrm{x}+16=0\) and \(\mathrm{x}^2+\mathrm{y}^2=\mathrm{a}^2\) intersect at two distinct points if
- A \(\mathrm{a} < 2\)
- B \(2 < \) a \( < 8\)
- C \(a>8\)
- D \(\mathbf{a}=2\)
Answer & Solution
Correct Answer
(B) \(2 < \) a \( < 8\)
Step-by-step Solution
Detailed explanation
Hints : \(C_1(5,0) \quad r_1=\sqrt{25-16}=3\)…
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