WBJEE · Chemistry · Some Basic Concepts of Chemistry
The weight of oxalic acid that will be required to prepare a \(1000 \mathrm{mL}(\mathrm{N} / 20)\) solution is
- A \(126 / 100 \mathrm{g}\)
- B \(63 / 40 \mathrm{g}\)
- C \(63 / 20 \mathrm{g}\)
- D \(126 / 20 \mathrm{g}\)
Answer & Solution
Correct Answer
(C) \(63 / 20 \mathrm{g}\)
Step-by-step Solution
Detailed explanation
\(w=\frac{N E V}{1000}=\frac{1}{20} \times \frac{63 \times 1000}{1000}=\frac{63}{20} g\)
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