WBJEE · Chemistry · Solutions
When \(20 \mathrm{~g}\) of naphthoic acid \(\left(\mathrm{C}_{11} \mathrm{H}_{8} \mathrm{O}_{2}\right)\) is dissolved in \(50 \mathrm{~g}\) of benzene, a freezing point depression of \(2 \mathrm{~K}\) is observed. The vant Hoff factor (i) is \(\left[\mathrm{K}_{\mathrm{f}}=1.72^{\circ} \mathrm{K} \mathrm{kg} \mathrm{mol}^{-1}\right]\)
- A \(0.5\)
- B \(1.0\)
- C \(2.0\)
- D \(3.0\)
Answer & Solution
Correct Answer
(A) \(0.5\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{l} \Delta \mathrm{T}_{\mathrm{f}}=\mathrm{i} \mathrm{K}_{\mathrm{f}} \mathrm{m} \\ 2=\mathrm{i} \times 1.72 \times \frac{20 \times 1000}{172 \times 50} \\ \therefore \mathrm{i}=\frac{2}{0.01 \times 2 \times 200}=\frac{1}{2}=0.5 \end{array}\)
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