WBJEE · Chemistry · Chemical Bonding and Molecular Structure
The paramagnetic behaviour of \(\mathrm{B}_{2}\) is due to the presence of
- A two unpaired electrons in \(\pi^{*}\) MO
- B two unpaired electrons in \(\pi\) MO
- C two unpaired electrons in \(\dot{\sigma}\) MO
- D two unpaired electrons in \(\sigma^{*}\) MO
Answer & Solution
Correct Answer
(A) two unpaired electrons in \(\pi^{*}\) MO
Step-by-step Solution
Detailed explanation
\(B_{2}=5+5=10 e^{-}\) \[ =\sigma 1 s^{2} \dot{\sigma} 1 s^{2}, \sigma 2 s^{2} \dot{\sigma} 2 s^{2}, \pi 2 p_{x}^{1}, \pi 2 p_{y}^{\prime} \] Due to the presence of 2 unpaired electrons, in \(\pi\) bonding orbitals, \(B_{2}\) shows paramagnetic behaviour.
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