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WBJEE · Maths · Properties of Triangles

In triangle \(\mathrm{ABC}, \mathrm{a}=2, \mathrm{~b}=3\) and \(\sin \mathrm{A}=\frac{2}{3}\), then \(\mathrm{B}\) is equal to

  1. A \(30^{\circ}\)
  2. B \(60^{\circ}\)
  3. C \(90^{\circ}\)
  4. D \(120^{\circ}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(90^{\circ}\)

Step-by-step Solution

Detailed explanation

Hints: \(\frac{a}{\sin A}=\frac{b}{\sin B}\) \(\sin B=\frac{b}{a} \cdot \sin A=\frac{3}{2} \cdot \frac{2}{3}=1\) \[ \mathrm{B}=\frac{\pi}{2} \]