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WBJEE · Chemistry · States of Matter

The RMS velocity of CO gas molecules at \(27^{\circ} \mathrm{C}\) is approximately \(1000 \mathrm{m} / \mathrm{s}\). For molecules at \(600 \mathrm{K}\), the RMS velocity is approximately

  1. A \(2000 \mathrm{m} / \mathrm{s}\)
  2. B \(1414 \mathrm{m} / \mathrm{s}\)
  3. C \(1000 \mathrm{m} / \mathrm{s}\)
  4. D \(1500 \mathrm{m} / \mathrm{s}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(1414 \mathrm{m} / \mathrm{s}\)

Step-by-step Solution

Detailed explanation

As trom the formula, \(v_{\text {ms }}=\sqrt{\frac{3 R T}{M}}\) Given that \(\left(v_{\text {rms }}\right)_{CO}=1000 \mathrm{m} / \mathrm{s}\) \((Temp )_{CO}=27^{\circ} \mathrm{C}=300 \mathrm{K}\) \((Temp.) _{\mathrm{N}_{\mathrm{2}}}=600 \mathrm{K}\) Now putting the values, we…