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WBJEE · Chemistry · Chemical Kinetics

Under the same reaction conditions, initial concentration of \(1.386 \mathrm{~mol} \mathrm{dm}^{-3}\) of a substance becomes half in \(40 \mathrm{~s}\) and 20 s through first-order and zero-order kinetics respectively. Ratio \(\left(\frac{k_{1}}{k_{0}}\right)\) of the rate constants for first-order \(\left(k_{1}\right)\) and zero-order \(\left(\mathrm{k}_{0}\right)\) of the reactions is

  1. A \(0.5 \mathrm{~mol}^{-1} \mathrm{dm}^{3}\)
  2. B \(0.5 \mathrm{~mol} \mathrm{dm}^{-3}\)
  3. C \(1.0 \mathrm{~mol} \mathrm{dm}^{-3}\)
  4. D \(2.0 \mathrm{~mol}^{-1} \mathrm{dm}^{3}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(0.5 \mathrm{~mol}^{-1} \mathrm{dm}^{3}\)

Step-by-step Solution

Detailed explanation

For First order reaction \(\mathrm{t}_{1 / 2}=\frac{0.693}{\mathrm{k}_{1}} \Rightarrow \mathrm{k}_{1}=\frac{0.693}{40} \mathrm{~s}^{-1}\quad_{-} \text {(i) }\) For Zero order reaction…