WBJEE · Physics · Thermal Properties of Matter
Consider an engine that absorbs 130 cal of heat from a hot reservoir and delivers 30 cal heat to a cold reservoir in each cycle. The engine also consumes 2 J energy in each cycle to overcome friction. If the engine works at 90 cycles per minute, what will be the maximum power delivered to the load? [Assume the thermal equivalent of heat is \(4.2 \mathrm{~J} / \mathrm{cal}]\)
- A \(816 \mathrm{~W}\)
- B \(819 \mathrm{~W}\)
- C \(627 \mathrm{~W}\)
- D \(630 \mathrm{~W}\)
Answer & Solution
Correct Answer
(C) \(627 \mathrm{~W}\)
Step-by-step Solution
Detailed explanation
Hint: work done per cycle \(=100 \times 4.2-2=418 \mathrm{~J}\) Total work done \(=418 \times 90\) Power \(=\frac{418 \times 90}{60}=627 \mathrm{~W}\)
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