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WBJEE · Chemistry · Hydrocarbons

The number of alkene (s) which can produce 2 -butanol by the successive treatment of
(i) \(\mathrm{B}_{2} \mathrm{H}_{6}\) in tetrahydrofuran solvent and
(ii) alkaline \(\mathrm{H}_{2} \mathrm{O}_{2}\) solution is

  1. A 1
  2. B 2
  3. C 3
  4. D 4
Verified Solution

Answer & Solution

Correct Answer

(B) 2

Step-by-step Solution

Detailed explanation

The number of alkene(s) that can produce 2-butanol by the successive treatment of \(\mathrm{B}_{2} \mathrm{H}_{6}\) in tetrahydrofuran solvent and alkaline \(\mathrm{H}_{2} \mathrm{O}_{2}\) solution is \(2 .\) The alkenes are \(c i s\) -but -2 - ene and trans-but-2-ene. The…