WBJEE · Chemistry · Solid State
The ground state magnetic property of \(\mathrm{B}_{2}\) and
\(\mathrm{C}_{2}\) molecules will be
- A \(\mathrm{B}_{2}\) paramagnetic and \(\mathrm{C}_{2}\) diamagnetic
- B \(\mathrm{B}_{2}\) diamagnetic and \(\mathrm{C}_{2}\) paramagnetic
- C Both are diamagnetic
- D Both are paramagnetic
Answer & Solution
Correct Answer
(A) \(\mathrm{B}_{2}\) paramagnetic and \(\mathrm{C}_{2}\) diamagnetic
Step-by-step Solution
Detailed explanation
According to molecular orbital theory, outer configuration for \[ \left[\mathrm{C}_{2}\right]=\mathrm{C}_{12} \rightarrow \pi p_{x}^{2}=\pi p_{y}^{2} \] Thus, is diamagnetic in nature. \[ \left[\mathrm{B}_{2}\right]=\mathrm{B}_{10}->\pi p_{x}^{1}=\pi p_{y}^{1} \] Thus, is…
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