WBJEE · Chemistry · Redox Reactions
The equivalent weight of \(\mathrm{Na}_2 \mathrm{~S}_2 \mathrm{O}_3(\) Gram molecular weight \(=M)\) in the given reaction is \(\mathrm{I}_2+2 \mathrm{Na}_2 \mathrm{~S}_2 \mathrm{O}_3=2 \mathrm{NaI}+\mathrm{Na}_2 \mathrm{~S}_4 \mathrm{O}_6\)
- A M/2
- B M
- C 2M
- D M/4
Answer & Solution
Correct Answer
(B) M
Step-by-step Solution
Detailed explanation
Hint: \(\mathrm{I}_2+2 \mathrm{Na}_2 \stackrel{+2}{\mathrm{~S}}_2 \mathrm{O}_3=2 \mathrm{NaI}+\mathrm{Na}_2 \stackrel{+2.5}{\mathrm{~S}_4} \mathrm{O}_6\) \(n \cdot f=2 \times 0.5=1\) \(\therefore\) Number of moles of electron lost per mole of…
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