WBJEE · Chemistry · Thermodynamics (C)
The value of \(\Delta H\) for cooling 2 mole of an ideal monoatomic gas from \(225^{\circ} \mathrm{C}\) to \(125^{\circ} \mathrm{C}\) at constant pressure will be [given \(\left.C_{p}=\frac{5}{2} R\right]\)
- A \(250 \mathrm{R}\)
- B \(-500 R\)
- C \(500 \mathrm{R}\)
- D \(-250 R\)
Answer & Solution
Correct Answer
(B) \(-500 R\)
Step-by-step Solution
Detailed explanation
\(\Delta H=-n C_{p} \Delta T=-2 \times \frac{5}{2} R(225-125)\) \[ =-5 R(100)=-500 R \]
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