WBJEE · Chemistry · Electrochemistry
If electrolysis of aqueous CuSO \(_{4}\) solution is carried out using Cu-electrodes, the reaction taking place at the anode is
- A \(\mathrm{H}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{H}\)
- B \(\mathrm{Cu}^{2+}(\mathrm{aq})+2 \mathrm{e}^{-} \rightarrow \mathrm{Cu}(\mathrm{s})\)
- C \(\mathrm{SO}_{4}^{2-}(\mathrm{aq})-2 \mathrm{e}^{-} \rightarrow \mathrm{SO}_{4}\)
- D \(\mathrm{Cu}(\mathrm{s})-2 e^{-} \rightarrow \mathrm{Cu}^{2+}(\mathrm{aq})\)
Answer & Solution
Correct Answer
(D) \(\mathrm{Cu}(\mathrm{s})-2 e^{-} \rightarrow \mathrm{Cu}^{2+}(\mathrm{aq})\)
Step-by-step Solution
Detailed explanation
Electrolysis of copper sulphate solution using Cu-electrodes, Ions present : \(\mathrm{Cu}^{2+}, \mathrm{H}^{+}, \mathrm{SO}_{4}^{2-}, \mathrm{OH}^{-}\) At cathode \(\mathrm{Cu}^{2+}(a q)+2 e^{-} \rightarrow \mathrm{Cu}(s)\) At anode…
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