WBJEE · Chemistry · Carboxylic Acid Derivatives
The compound, which evolves carbon dioxide on treatment with aqueous solution of sodium bicarbonate at \(25^{\circ} \mathrm{C},\) is
- A \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}\)
- B \(\mathrm{CH}_{3} \mathrm{COCl}\)
- C \(\mathrm{CH}_{3} \mathrm{CONH}_{2}\)
- D \(\mathrm{CH}_{3} \mathrm{OOOC}_{2} \mathrm{H}_{5}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{CH}_{3} \mathrm{COCl}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{CH}_{3}-\mathrm{C}O-\mathrm{Cl}\) hydrolyses to form \(\mathrm{CH}_{3} \mathrm{COOH}\) even at \(25^{\circ} \mathrm{C},\) which subsequently reacts with \(NaHCO_{3}\) (sodium bicarbonate) present in the same medium to form carbon dioxide…
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