WBJEE · Chemistry · Thermodynamics (C)
The amount of the heat released when \(20 \mathrm{ml} 0.5 \mathrm{M} \mathrm{NaOH}\) is mixed with \(100 \mathrm{ml} 0.1 \mathrm{M} \mathrm{HCl}\) is \(\mathrm{x} \mathrm{kJ}\). The heat of neutralization is
- A \(-100 \mathrm{~xkJ} / \mathrm{mol}\)
- B \(-50 \mathrm{~kJ} / \mathrm{mol}\)
- C \(+100 \mathrm{~xkJ} / \mathrm{mol}\)
- D \(+50 \mathrm{~xkJ} / \mathrm{mol}\)
Answer & Solution
Correct Answer
(A) \(-100 \mathrm{~xkJ} / \mathrm{mol}\)
Step-by-step Solution
Detailed explanation
Hints: \(\underset{20 \times 05}{\mathrm{NaOH}}+\underset{100 \times 01}{\mathrm{HCl}} \rightarrow \mathrm{NaCl}+\underset{10 \text { millimole prodiral }}{\mathrm{H}_2 \mathrm{O}}\) During formation of 10 millimole of \(\mathrm{H}_2 \mathrm{O}\) the heat released is…
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