WBJEE · Chemistry · p Block Elements (Group 15, 16, 17 & 18)
Sulphuryl chloride \(\left(\mathrm{SO}_{2} \mathrm{Cl}_{2}\right.\) ) reacts with white phosphorus \(\left(\mathrm{P}_{4}\right)\) to give
- A \(P C l_{5}, S O_{2}\)
- B \(\mathrm{OPCl}_{3}, \mathrm{SOCl}_{2}\)
- C \(P C l_{5}\). \(S O_{2}, S_{2} C_{2}\)
- D \(\mathrm{OPCl}_{3}, \mathrm{SO}_{2}, \mathrm{S}_{2} \mathrm{Cl}_{2}\)
Answer & Solution
Correct Answer
(A) \(P C l_{5}, S O_{2}\)
Step-by-step Solution
Detailed explanation
When sulphuryl chloride \(\left(\mathrm{SO}_{2} \mathrm{Cl}_{2}\right)\), reacts with white phosphorus \(\left(\mathrm{P}_{4}\right),\) it give phosphorus pentachloride \(\left(\mathrm{PCl}_{5}\right)\) and sulphur dioxide \(\left(\mathrm{SO}_{2}\right)\). The reaction is as…
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