WBJEE · Maths · Matrices
Let \(A=\left(\begin{array}{lll}3 & 0 & 3 \\ 0 & 3 & 0 \\ 3 & 0 & 3\end{array}\right) .\) Then, the roots of the equation \(\operatorname{det}\left(A-\lambda I_{3}\right)=0\) (where \(I_{3}\) is the identity matrix of order 3 ) are
- A 3,0,3
- B 0,3,6
- C 1,0,-6
- D 3,3,6
Answer & Solution
Correct Answer
(B) 0,3,6
Step-by-step Solution
Detailed explanation
We have, \[ A=\left[\begin{array}{lll} 3 & 0 & 3 \\ 0 & 3 & 0 \\ 3 & 0 & 3 \end{array}\right] \] Again, we have \[ \left|\begin{array}{ccc} 3-\lambda & 0 & 3 \\ 0 & 3-\lambda & 0 \\ 3 & 0 & 3-\lambda \end{array}\right|=0 \]…
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