WBJEE · Chemistry · Solutions
If \(p^{\circ}\) and \(p\) are the vapour pressure of the pure solvent and solution and \(n_{1}\) and \(n_{2}\) are the moles of solute and solvent respectively in the solution then the correct relation between \(p\) and \(p^{\circ}\) is
- A \(p^{\circ}=\rho\left[\frac{n_{1}}{n_{1}+n_{2}}\right]\)
- B \(D^{\circ}=p\left[\frac{n_{2}}{n_{1}+n_{2}}\right]\)
- C \(p=p^{\circ}\left[\frac{n_{2}}{n_{1}+n_{2}}\right]\)
- D \(p=p^{\circ}\left[\frac{n_{1}}{n_{1}+n_{2}}\right]\)
Answer & Solution
Correct Answer
(C) \(p=p^{\circ}\left[\frac{n_{2}}{n_{1}+n_{2}}\right]\)
Step-by-step Solution
Detailed explanation
Given, \[ \begin{array}{l} p^{\circ}= \text {vapour pressure of pure solvent}\\ p=\text { vapour pressure of solution } \\ n_{1}=\text { moles of solute } \\ n_{2}=\text { moles of solvent } \end{array} \] Thus, according to Raoult's law.…
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