WBJEE · Maths · Definite Integration
If \(\mathrm{I}=\int_0^{\mathrm{I}} \frac{\mathrm{dx}}{1+\mathrm{x}^{\pi / 2}}\), then
- A \(\log _{\mathrm{e}} 2 < 1 < \pi / 4\)
- B \(\log _{\mathrm{e}} 2>1\)
- C \(\mathrm{I}=\pi / 4\)
- D \(\mathrm{I}=\log _{\mathrm{e}} 2\)
Answer & Solution
Correct Answer
(A) \(\log _{\mathrm{e}} 2 < 1 < \pi / 4\)
Step-by-step Solution
Detailed explanation
Hints: \(\mathrm{x}^2 \frac{1}{1+x^{\frac{\pi}{2}}}>\frac{1}{1+x}\) \(\frac{\pi}{4}>\mathrm{I}>(\log (1+\mathrm{x})), \quad \frac{\pi}{4}>\mathrm{I}>\log 2\)
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