WBJEE · Maths · Binomial Theorem
If \(A\) and \(B\) are coefficients of \(x^{\mathrm{n}}\) in the expansions of \((1+x)^{2 \mathrm{n}}\) and \((1+x)^{2 \mathrm{n}-1}\) respectively, then \(\mathrm{A} / \mathrm{B}\) is equal to
- A 4
- B 2
- C 9
- D 6
Answer & Solution
Correct Answer
(B) 2
Step-by-step Solution
Detailed explanation
\(\begin{array}{r}\text {Hints: } A={ }^{2 n} C_n \\ B={ }^{2 n-1} C_n \end{array}\) \(\frac{\mathrm{A}}{\mathrm{B}}=\frac{{ }^{2 \mathrm{n}} \mathrm{C}_{\mathrm{n}}}{{ }^{2 \mathrm{n}-1} \mathrm{C}_{\mathrm{n}}}=\frac{2 \mathrm{n}}{\mathrm{n}}=2\)
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