WBJEE · Chemistry · Coordination Compounds
In the brown ring complex \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5}(\mathrm{NO})\right] \mathrm{SO}_{4}\)
nitric oxide behaves as
- A \(\mathrm{NO}^{+}\)
- B neutral NO molecule
- C \(\mathrm{NO}^{-}\)
- D \(\mathrm{NO}^{2-}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{NO}^{+}\)
Step-by-step Solution
Detailed explanation
In Fe-complexes, NO behaves as \(\mathrm{NO}^{+}\).
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