WBJEE · Chemistry · s Block Elements
\[
\begin{aligned}
&\text { The decreasing order of basic character of }\\
&\mathrm{K}_{2} \mathrm{O}, \mathrm{BaO}, \mathrm{CaO} \text { and } \mathrm{MgO} \text { is }
\end{aligned}
\]
- A \(\mathrm{K}_{2} \mathrm{O}>\mathrm{BaO}>\mathrm{CaO}>\mathrm{Mg} \mathrm{O}\)
- B \(\mathrm{K}_{2} \mathrm{O}>\mathrm{CaO}>\mathrm{BaO}>\mathrm{MgO}\)
- C \(\mathrm{MgO}>\mathrm{BaO}>\mathrm{CaO}>\mathrm{K}_{2} \mathrm{O}\)
- D \(\mathrm{MgO}>\mathrm{CaO}>\mathrm{BaO}>\mathrm{K}_{2} \mathrm{O}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{K}_{2} \mathrm{O}>\mathrm{BaO}>\mathrm{CaO}>\mathrm{Mg} \mathrm{O}\)
Step-by-step Solution
Detailed explanation
On the basis of electropositivity of metal, the order of basic character is \[ \mathrm{K}_{2} \mathrm{O}>\mathrm{BaO}>\mathrm{CaO}>\mathrm{MgO} \]
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