WBJEE · Chemistry · Structure of Atom
The electronic transitions from \(\mathrm{n}=2\) to \(\mathrm{n}=1\) will produce shortest wavelength in (where \(\mathrm{n}=\) principal quantum state)
- A \(\mathrm{Li}^{+2}\)
- B \(\mathrm{He}^{+}\)
- C \(\mathrm{H}\)
- D \(\mathrm{H}^{+}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{Li}^{+2}\)
Step-by-step Solution
Detailed explanation
Hints: \(\frac{1}{\lambda}=\mathrm{z}^2 \cdot \mathrm{R}_{\mathrm{H}}\left[1 / \mathrm{n}_1^2-1 / \mathrm{n}_2^2\right]\)…
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