WBJEE · Chemistry · Ionic Equilibrium
A weak acid of dissociation constant \(10^{-5}\) is being titrated with aqueous \(\mathrm{NaOH}\) solution. The \(\mathrm{pH}\) at the point of one-third neutralisation of the acid will be
- A \(5+\log 2-\log 3\)
- B \(5-\log 2\)
- C \(5-\log 3\)
- D \(5-\log 6\)
Answer & Solution
Correct Answer
(B) \(5-\log 2\)
Step-by-step Solution
Detailed explanation
Hints: \(\mathrm{K}_{\mathrm{a}}=10^{-5} \Rightarrow \mathrm{pK}_{\mathrm{a}}=-\log \mathrm{K}_{\mathrm{a}}=-\log 10^{-5}=5\)…
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