TS EAMCET · Physics · Wave Optics
Young's double slit experiment is performed with monochromatic light of wavelength 6000 A . If the intensity of light at a point on the screen where path difference of \(2000 Å\) is \(I_1\) and the intensity of light at a point on the screen where the path difference is \(1000 Å\) is \(I_2\), then \(I_1: I_2=\)
- A \(1: 3\)
- B \(2: 1\)
- C \(1: 1\)
- D \(4: 5\)
Answer & Solution
Correct Answer
(A) \(1: 3\)
Step-by-step Solution
Detailed explanation
Intensity \(I=I_0 \cos ^2 \phi\) And \(\phi=\frac{2 \pi}{\pi} . \Delta x\) where \(\Delta x=\) path difference \(\phi_1=\frac{2 \pi}{6000} \times 2000=120^{\circ}\) Similarly, \(\phi_2=\frac{2 \pi}{6000} \times 1000=60^{\circ}\)…
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