TS EAMCET · Physics · Mechanical Properties of Fluids
A solid metal sphere released in a vertical liquid column has attained terminal velocity in the downward direction. The magnitudes of viscous force, buoyant force and gravitational force acting on it are \(\mathrm{F}_{\mathrm{v}}, \mathrm{F}_{\mathrm{B}}\) and \(\mathrm{F}_{\mathrm{W}}\) respectively. Then the correct relation between them is
- A \(\mathrm{F}_{\mathrm{B}}>\mathrm{F}_{\mathrm{V}}=\mathrm{F}_{\mathrm{W}}\)
- B \(\mathrm{F}_{\mathrm{W}}=\mathrm{F}_{\mathrm{V}}+\mathrm{F}_{\mathrm{B}}\)
- C \(\mathrm{F}_{\mathrm{B}}=\mathrm{F}_{\mathrm{W}}+\mathrm{F}_{\mathrm{V}}\)
- D \(\mathrm{F}_{\mathrm{V}}=\mathrm{F}_{\mathrm{B}}+\mathrm{F}_{\mathrm{W}}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{F}_{\mathrm{W}}=\mathrm{F}_{\mathrm{V}}+\mathrm{F}_{\mathrm{B}}\)
Step-by-step Solution
Detailed explanation
Gravitational force, \(\left(\mathrm{F}_{\mathrm{w}}\right)=\) Viscous Force \(\left(\mathrm{F}_{\mathrm{v}}\right)+\) Buoyant Force \(\left(\mathrm{F}_{\mathrm{B}}\right)\)
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