TS EAMCET · Physics · Motion In One Dimension
A body moving with uniform acceleration, travels a distance of 25 m in the fourth second and 37 m in the sixth second. The distance covered by the body in the next two seconds is
- A 63 m
- B 84 m
- C 49 m
- D 92 m
Answer & Solution
Correct Answer
(D) 92 m
Step-by-step Solution
Detailed explanation
For uniformly accelerated motion, \(\begin{aligned} & \mathrm{S}_{\mathrm{n}}=\mathrm{u}+(2 \mathrm{n}-1) \frac{\mathrm{a}}{2} \\ & \therefore \quad 25=\mathrm{u}+(2 \times 4-1) \frac{\mathrm{a}}{2}=\mathrm{u}+\frac{7}{2} \mathrm{a} \end{aligned}\) Again,…
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