TS EAMCET · Physics · Mechanical Properties of Solids
What is the work done in stretching a uniform metal wire of length from 2 m to 2.004 m with an area of cross section \(10^{-6} \mathrm{~m}^2 ?\) [Young's modulus of the wire = 2 × 1011 N/m2]
- A 1.6 J
- B 0.8 J
- C 8 J
- D 16 J
Answer & Solution
Correct Answer
(B) 0.8 J
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { Work done }=\frac{1}{2} \mathrm{Kx}^2 \\ & =\frac{1}{2} \frac{\mathrm{yA}}{\ell} \times(\Delta \ell)^2=\frac{1}{2} \times \frac{2 \times 10^{11} \times 10^{-6}}{2} \times(0.004)^2 \\ & =0.8 \mathrm{~J}\end{aligned}\)
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