TS EAMCET · Physics · Electromagnetic Waves
An electromagnetic wave of frequency 3.0 MHz passes from vacuum into a non-magnetic medium with permittivity, \(\epsilon=16 \epsilon_0\). Where, \(\epsilon_0\) is the free space permittivity. The change in wavelength is
- A \(-75 \mathrm{~m}\)
- B \(+75 \mathrm{~m}\)
- C \(-50 \mathrm{~m}\)
- D \(+50 \mathrm{~m}\)
Answer & Solution
Correct Answer
(A) \(-75 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
Given, frequency of EM wave, \(\begin{aligned} f & =3 \mathrm{MHz} \\ & =3 \times 10^6 \mathrm{~Hz} \end{aligned}\) and permittivity of non-magnetic medium, \(\varepsilon=16 \varepsilon_0\) Wavelength of EM wave,…
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