TS EAMCET · Physics · Motion In Two Dimensions
The horizontal and vertical displacements \(x\) and \(y\) of a projectile at a given time \(t\) are given by \(x=6 t\) metre and \(y=8 t-5 t^2\) metre. The range of the projectile in metre is
- A \(9.6\)
- B \(10.6\)
- C \(19.2\)
- D \(38.4\)
Answer & Solution
Correct Answer
(A) \(9.6\)
Step-by-step Solution
Detailed explanation
\[ \begin{aligned} & x=(u \cos \theta) t=6 t \\ & \quad y=(u \sin \theta) t-\frac{1}{2} g t^2=8 t-5 t^2 \end{aligned} \] Therefore, \(u \sin \theta=8\) \(u \cos \theta=6\)…
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