TS EAMCET · Physics · Work Power Energy

An object $A$ of mass $20 kg$ and travelling at $20 m s^{- 1}$ crashes into another object $B$ of mass $200 kg$ and travelling at $10 m s^{- 1},$ in the same direction. After the collision, object $A$ bounces back in opposite direction at a speed of $10 m s^{- 1}$ . The speed of the object $B$ after the collision is

A $13 m s^{- 1}$
B $12 m s^{- 1}$
C $14 m s^{- 1}$
D $20 m s^{- 1}$

Verified Solution

Answer & Solution

Correct Answer

(A) $13 m s^{- 1}$

Step-by-step Solution

Detailed explanation

Since net force in collision on the system is zero, so from conservation of momentum, we have maua+mbub=mava+mbvb ⇒20×20+200×10=20×-10+200×vb ⇒2400=-200+200×vb ⇒vb=2600200=13 m s-1

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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An object A of mass 20 kg and travelling at 20 m s-1 crashes into another object B of mass 200 kg and travelling at 10 m s-1, in the same direction. After the collision, object A bounces back in opposite direction at a speed of 10 m s-1. The speed of the object B after the collision is

Step-by-step Solution