TS EAMCET · Physics · Magnetic Properties of Matter
If \(B_V\) and \(B_H\) are respectively the vertical and horizontal components of the earth's magnetic field at a place where the angle of dip is \(60^{\circ}\), then the total magnetic field at that place is
- A \(\sqrt{3} \mathrm{~B}_{\mathrm{H}}\)
- B \(\sqrt{3} \mathrm{~B}_{\mathrm{V}}\)
- C \(\frac{2}{\sqrt{3}} \mathrm{~B}_{\mathrm{V}}\)
- D \(\frac{\sqrt{3}}{2} B_H\)
Answer & Solution
Correct Answer
(C) \(\frac{2}{\sqrt{3}} \mathrm{~B}_{\mathrm{V}}\)
Step-by-step Solution
Detailed explanation
\(B = \frac{B_V}{\sin \theta}\) \(B = \frac{B_V}{\sin 60^{\circ}}\) \(B = \frac{B_V}{\frac{\sqrt{3}}{2}}\) \(B = \frac{2}{\sqrt{3}} B_V\)
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