TS EAMCET · Physics · Current Electricity
A wire, \(10 \mathrm{~m}\) long, has a resistance of \(40 \Omega\). It is connected in series with a resistance box of resistance \(R\) and a \(2 \mathrm{~V}\) storage cell. If the potential gradient along the wire is \(0.1 \mathrm{mV} / \mathrm{cm}\), then the value of \(R\) is
- A \(260 \Omega\)
- B \(760 \Omega\)
- C \(960 \Omega\)
- D \(1060 \Omega\)
Answer & Solution
Correct Answer
(B) \(760 \Omega\)
Step-by-step Solution
Detailed explanation
Given that, resistance of wire, \(R_1=40 \Omega\) Length of wire, \(l=10 \mathrm{~m}\) Resistance of resistance box \(=R\) Potential gradient of wire,…
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