TS EAMCET · Physics · Thermal Properties of Matter
The thickness of a uniform rectangular metal plate is 5 mm and the area of each surface is \(5 \mathrm{~cm}^2\). In steady state, the temperature difference between the two surfaces of the plate is \(14^{\circ} \mathrm{C}\). If the heat flowing through the plate in one second from one surface to the other surface is 42 J , then the thermal conductivity of the metal is
- A \(90 \mathrm{Wm}^{-1} \mathrm{~K}^{-1}\)
- B \(30 \mathrm{Wm}^{-1} \mathrm{~K}^{-1}\)
- C \(45 \mathrm{Wm}^{-1} \mathrm{~K}^{-1}\)
- D \(60 \mathrm{Wm}^{-1} \mathrm{~K}^{-1}\)
Answer & Solution
Correct Answer
(B) \(30 \mathrm{Wm}^{-1} \mathrm{~K}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\Delta \mathrm{x}=5 \mathrm{~mm}, \mathrm{~A}=5 \mathrm{~cm}^2, \Delta \mathrm{~T}=14^{\circ} \mathrm{C}, \mathrm{Q}=42 \mathrm{~W}\) \(\therefore\) At steady state,…
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