TS EAMCET · Physics · Mechanical Properties of Fluids
A block of iron contains a hollow cavity as shown below. The block weighs \(6000 \mathrm{~N}\) in air and \(4000 \mathrm{~N}\) in water. If the density of iron and water are \(6 \mathrm{~g} / \mathrm{cm}^3\) and \(1 \mathrm{~g} / \mathrm{cm}^3\), then the volume of the cavity is (assume, \(g=10 \mathrm{~m} / \mathrm{s}^2\) )
- A \(0.05 \mathrm{~m}^3\)
- B \(0.5 \mathrm{~m}^3\)
- C \(0.25 \mathrm{~m}^3\)
- D \(0.1 \mathrm{~m}^3\)
Answer & Solution
Correct Answer
(D) \(0.1 \mathrm{~m}^3\)
Step-by-step Solution
Detailed explanation
Weight of block in air, \(w_{\text {air }}=6000 \mathrm{~N}\) Weight of block in water, \(w_{\text {water }}=4000 \mathrm{~N}\) According to figure given, volume of cavity, \(V_1=\) volume of water displaced - volume of iron…
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