TS EAMCET · Physics · Center of Mass Momentum and Collision
Particles of masses \(m, 2 m, 3 m, \ldots n m\) grams are placed on the same line at distance \(l, 2 l, 3 l \ldots n l\) \(\mathrm{cm}\) from a fixed point. The distance of centre of mass of the particles from the fixed point in centimetre is
- A \(\frac{(2 n+1) l}{3}\)
- B \(\frac{l}{n+1}\)
- C \(\frac{n\left(n^2+1\right) l}{2}\)
- D \(\frac{2 l}{n\left(n^2+1\right)}\)
Answer & Solution
Correct Answer
(A) \(\frac{(2 n+1) l}{3}\)
Step-by-step Solution
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