TS EAMCET · Physics · Semiconductors
A \(p\) - \(n\) junction diode can withstand upto \(20 \mathrm{~mA}\) current under forward bias. The diode has a potential difference of \(0.5 \mathrm{~V}\) across it, which is assumed to be independent of current. What is the maximum voltage of the battery used to forward bias the diode when a resistance of \(125 \Omega\) is connected in series with it?
- A \(3.0 \mathrm{~V}\)
- B \(2.5 \mathrm{~V}\)
- C \(3.2 \mathrm{~V}\)
- D \(2.0 \mathrm{~V}\)
Answer & Solution
Correct Answer
(A) \(3.0 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
Given, potential difference across diode, \(V_D=0.5 \mathrm{~V}\) Maximum current in forward bias, \(i=20 \mathrm{~mA}=20 \times 10^{-3} \mathrm{~A}\) \(\Rightarrow\) Resistance of diode, \(R_D=\frac{V_D}{i}=\frac{0.5}{20 \times 10^{-3}}=25 \Omega\) Now, another resistance of…
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