TS EAMCET · Physics · Mechanical Properties of Solids
Two wires A and B made of same material and areas of cross-section in the ratio \(1: 2\) are stretched by same force. If the masses of the wires \(A\) and \(B\) are in the ratio \(2: 3\), then the ratio of the elongations of the wires A and B is
- A \(1: 2\)
- B \(8: 3\)
- C \(1: 3\)
- D \(4: 3\)
Answer & Solution
Correct Answer
(B) \(8: 3\)
Step-by-step Solution
Detailed explanation
\(\frac{\Delta L_A}{\Delta L_B} = \frac{F L_A / (A_A Y)}{F L_B / (A_B Y)} = \frac{L_A}{L_B} \frac{A_B}{A_A}\) \(\frac{m_A}{m_B} = \frac{\rho A_A L_A}{\rho A_B L_B} = \frac{A_A}{A_B} \frac{L_A}{L_B}\)…
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