ExamBro
ExamBro
TS EAMCET · Physics · Units and Dimensions

If L and C are inductance and capacitance respectively, then the dimensional formula of \((\mathrm{LC})^{-\frac{1}{2}}\) is

  1. A \(\left[\mathrm{M}^0 \mathrm{~L}^0 \mathrm{~T}^{-1}\right]\)
  2. B \(\left[\mathrm{M}^1 \mathrm{~L}^1 \mathrm{~T}^{-1}\right]\)
  3. C \(\left[\mathrm{M}^0 \mathrm{~L}^1 \mathrm{~T}^1\right]\)
  4. D \(\left[\mathrm{M}^0 \mathrm{~L}^0 \mathrm{~T}^{-2}\right]\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\left[\mathrm{M}^0 \mathrm{~L}^0 \mathrm{~T}^{-1}\right]\)

Step-by-step Solution

Detailed explanation

\([L] = [ML^2T^{-2}A^{-2}]\) \([C] = [M^{-1}L^{-2}T^4A^2]\) \([LC] = [ML^2T^{-2}A^{-2}][M^{-1}L^{-2}T^4A^2] = [T^2]\) \([ (LC)^{-\frac{1}{2}} ] = ([T^2])^{-\frac{1}{2}} = [T^{-1}]\) \([ (LC)^{-\frac{1}{2}} ] = [M^0 L^0 T^{-1}]\)
Same subject
Explore more questions on app
From TS EAMCET
Explore more questions on app