TS EAMCET · Physics · Waves and Sound
Two identical wires have a fundamental frequency \(f_0\) when kept under the same tension \(T\). If the tension of one wire is increased by \(\Delta T\), then the \(N\) beats occur when both wires oscillate simultaneously.
- A \(\frac{\Delta T}{T}=\left(\frac{f_0+N}{f_0}\right)^2-1\)
- B \(\frac{\Delta T}{T}=\left(\frac{f_0}{f_0-N}\right)^2-1\)
- C \(\frac{\Delta T}{T}=\left(\frac{f_0-N}{f_0}\right)^2+1\)
- D \(\frac{\Delta T}{T}=\left(\frac{f_0+N}{f_0}\right)^2\)
Answer & Solution
Correct Answer
(A) \(\frac{\Delta T}{T}=\left(\frac{f_0+N}{f_0}\right)^2-1\)
Step-by-step Solution
Detailed explanation
Fundamental frequency of the wire, \[ f_0=\frac{v}{2 L}, \text { where } v=\sqrt{\frac{T}{\mu}} \] \(\begin{array}{ll}\Rightarrow & f_0=\frac{1}{2 L} \sqrt{\frac{T}{\mu}} \\ \Rightarrow & f_0 \propto \sqrt{T}\end{array}\) Dividing Eq. (ii) by Eq. (i), we get…
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