TS EAMCET · Physics · Kinetic Theory of Gases
Two gases \(A\) and \(B\) are contained in two separate, but otherwise identical containers. Gas \(A\) consists of monatomic molecules, each with atomic mass of \(4 u\) whereas Gas \(B\) consists of rigid diatomic molecules, each with atomic mass of \(20 u\). If gas \(A\) is kept at \(27^{\circ} \mathrm{C}\), at what temperature should gas \(B\) be kept so that both have the same rms speed?
- A \(27^{\circ} \mathrm{C}\)
- B \(54^{\circ} \mathrm{C}\)
- C \(270^{\circ} \mathrm{C}\)
- D \(62^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(C) \(270^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
For monatomic gas \(A\), atomic mass of molecules of gas \(A, m_A=4 u\) and temperature of gas, \(T_A=27^{\circ} \mathrm{C}\) For diatomic gas \(B\), atomic mass of molecules of gas \(B\), \(m_B=2 \times 20 \mathrm{u}=40 \mathrm{u}\) Temperature of gas, \(B=\mathrm{T}_B\) Since,…
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