TS EAMCET · Physics · Work Power Energy
A body of mass \(3 \mathrm{~kg}\) is moving under the action of a force which causes a displacement of \(\left(\frac{t^3}{3}\right) \mathrm{m}\), where ' \(\mathrm{t}\) ' is time in seconds. The work done by the force in first 2 seconds is
- A \(2 \mathrm{~J}\)
- B \(3.8 \mathrm{~J}\)
- C \(5.2 \mathrm{~J}\)
- D \(24 \mathrm{~J}\)
Answer & Solution
Correct Answer
(D) \(24 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
Mass of body, \(\mathrm{m}=3 \mathrm{~kg}\) Displacement \(\mathrm{x}=\frac{\mathrm{t}^3}{3} \mathrm{~m}\) Velocity, \(v=\frac{d x}{d t}\) \[ =\mathrm{t}^2 \] from work energy theorem…
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