TS EAMCET · Physics · Laws of Motion
Two blocks of masses in the ratio \(\mathrm{m}: \mathrm{n}\) are connected by a light inextensible string passing over a frictionless fixed pulley. If the system of the blocks is released from rest, then the acceleration of the centre of mass of the system of the blocks is (g - acceleration due to gravity)
- A \(\left(\frac{m+n}{m-n}\right)^2 g\)
- B \(\left(\frac{\mathrm{m}-\mathrm{n}}{\mathrm{m}+\mathrm{n}}\right)^2 \mathrm{~g}\)
- C \(\left(\frac{m+n}{m-n}\right) g\)
- D \(\left(\frac{\mathrm{m}-\mathrm{n}}{\mathrm{m}+\mathrm{n}}\right) \mathrm{g}\)
Answer & Solution
Correct Answer
(B) \(\left(\frac{\mathrm{m}-\mathrm{n}}{\mathrm{m}+\mathrm{n}}\right)^2 \mathrm{~g}\)
Step-by-step Solution
Detailed explanation
\(a = \frac{(\mathrm{m}-\mathrm{n})\mathrm{g}}{\mathrm{m}+\mathrm{n}}\) \(a_{CM} = \frac{\mathrm{m}(-\mathrm{a}) + \mathrm{n}(\mathrm{a})}{\mathrm{m}+\mathrm{n}} = \frac{(\mathrm{n}-\mathrm{m})\mathrm{a}}{\mathrm{m}+\mathrm{n}}\)…
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