TS EAMCET · Physics · Mechanical Properties of Fluids
The terminal velocity of a liquid drop of radius ' \(r\) ' falling through air is \(v\). If two such drops are combined to form a bigger drop, the terminal velocity with which the bigger drop falls through air is (ignore any buoyant force due to air)
- A \(\sqrt{2} v\)
- B \(2 v\)
- C \(\sqrt[3]{4} v\)
- D \(\sqrt[3]{2} v\)
Answer & Solution
Correct Answer
(C) \(\sqrt[3]{4} v\)
Step-by-step Solution
Detailed explanation
Terminal velocity \(v=\frac{2}{9} \frac{r^2(\rho-\sigma) g}{\eta}\) When, the two drops of same radius \(r\) coalesce then radius of new drop is \(R\).…
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