TS EAMCET · Physics · Communication System
For an amplitude modulated wave, the maximum and minimum amplitudes are found to be 10 V and 2 V respectively. Then the modulation index is
- A \(\frac{1}{3}\)
- B \(\frac{3}{4}\)
- C \(\frac{1}{5}\)
- D \(\frac{2}{3}\)
Answer & Solution
Correct Answer
(D) \(\frac{2}{3}\)
Step-by-step Solution
Detailed explanation
For amplitude modulated wave, \(A_{\max }=10 \mathrm{~V}, \mathrm{~A}_{\min }=2 \mathrm{~V}\) \(\therefore\) Modulation index, \(\mu=\frac{\mathrm{A}_{\max }-\mathrm{A}_{\min }}{\mathrm{A}_{\max }+\mathrm{A}_{\min }}=\frac{10-2}{10+2}=\frac{2}{3}\)
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