TS EAMCET · Physics · Laws of Motion
The force required to move a body up a rough inclined plane is double the force required to prevent the body from sliding down the plane. The coefficient of friction, when the angle of inclination of the plane is \(60^{\circ}\) is
- A \(\frac{1}{3}\)
- B \(\frac{1}{\sqrt{2}}\)
- C \(\frac{1}{\sqrt{3}}\)
- D \(\frac{1}{2}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{\sqrt{3}}\)
Step-by-step Solution
Detailed explanation
For upward motion, \(F_{\mathrm{up}}=m g(\sin \theta+\mu \cos \theta)\) For downward motion, \(F_{\text {down }}=m g(\sin \theta-\mu \cos \theta)\) ...(ii) According to the question,…
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