TS EAMCET · Physics · Capacitance
A parallel plate capacitor of capacitance \(10 \mu \mathrm{~F}\) is charged by a 220 V supply. The capacitor is then disconnected from the supply and is connected to another uncharged parallel plate capacitor of capacitance \(12 \mu \mathrm{~F}\). The loss of electrostatic energy in this process is
- A 132 mJ
- B 220 mJ
- C 66 mJ
- D 110 mJ
Answer & Solution
Correct Answer
(A) 132 mJ
Step-by-step Solution
Detailed explanation
\(U_{loss} = \frac{1}{2} \frac{C_1 C_2}{C_1 + C_2} V_1^2\) \( = \frac{1}{2} \frac{(10 \times 10^{-6})(12 \times 10^{-6})}{ (10 \times 10^{-6}) + (12 \times 10^{-6})} (220)^2\) \( = \frac{1}{2} \frac{120 \times 10^{-12}}{22 \times 10^{-6}} (48400)\) \( = 0.132 \mathrm{~J}\)…
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