TS EAMCET · Physics · Mechanical Properties of Fluids
When a big drop of water is formed from \(n\) small drops of water, the energy loss is \(3 E\), where, \(E\) is the energy of the bigger drop. If \(R\) is the radius of the bigger drop and \(r\) is the radius of the smaller drop, then number of smaller drops \((n)\) is
- A \(\frac{4 R}{r^2}\)
- B \(\frac{4 R}{r}\)
- C \(\frac{2 R^2}{r}\)
- D \(\frac{4 R^2}{r^2}\)
Answer & Solution
Correct Answer
(D) \(\frac{4 R^2}{r^2}\)
Step-by-step Solution
Detailed explanation
The energy of \(n\) small drop - the energy of the bigger drop = Energy loss by bigger drop…
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