TS EAMCET · Physics · Atomic Physics
The radius and mass number of nucleus ' 1 ' is \(R_1\) and \(A_1\) respectively. The radius and mass number of nucleus ' 2 ' is \(R_2\) and \(A_2\) respectively. If \(A_2\) is larger than \(A_1\) by \(2 \%\), then \(R_2\) is larger than \(R_1\) by
- A \(\frac{2}{3} \%\)
- B \(1 \%\)
- C \(8 \%\)
- D \(\frac{3}{2} \%\)
Answer & Solution
Correct Answer
(A) \(\frac{2}{3} \%\)
Step-by-step Solution
Detailed explanation
For nucleus 1 \(\mathrm{R}_1=\mathrm{R}_0 \mathrm{~A}_1^{1 / 3}\) For nucleus 2 \(\mathrm{R}_2=\mathrm{R}_0 \mathrm{~A}_2^{1 / 3}\) Divide equation (ii) by (i)…
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